Question
when a sample of aluminum absorbed 9.85 j of heat its temperature increased from 23.2 C to 30.5 C. The mass of the sample was__ g.
Answers
DrBob222
q = mass x specific heat x delta T
9.85 J = mass Al x specific heat Al x (30.5 - 23.2)
You will need to look up the specific heat Al if it isn't given in the problem, substitute that into the equation and solve for mass Al.
Post your work if you get stuck.
9.85 J = mass Al x specific heat Al x (30.5 - 23.2)
You will need to look up the specific heat Al if it isn't given in the problem, substitute that into the equation and solve for mass Al.
Post your work if you get stuck.