Asked by Grant
The density of lead is 11.34 g/cm3 and the density of aluminum is 2.69 g/cm3. Find the radius of lead and aluminum spheres each having a mass of 70 kg. (Round your answers to two decimal places.)
Iam lost on everything I got this far
p(4/3)πr^3=m
r-(3m/(4πp))^1/3
Iam lost on everything I got this far
p(4/3)πr^3=m
r-(3m/(4πp))^1/3
Answers
Answered by
mathhelper
Well, 70 kg = 70,000 g
so the volume of the lead ball = 70000/11.34 cm^3 = 6172.8395 cm^3
the volume of the aluminium ball = 70000/2.69 cm^3 = 26022.305 cm^3
Now we'll use our sphere formula:
for the lead,
(4/3)πr^3 = 6172.8395
r^3 = 1473.65...
r = (1473.65...)^(1/3) = appr 11.38 cm
for the aluminum,
(4/3)πr^3 = 26022.305
r^3 = 6212.367...
r = 18.38 cm
so the volume of the lead ball = 70000/11.34 cm^3 = 6172.8395 cm^3
the volume of the aluminium ball = 70000/2.69 cm^3 = 26022.305 cm^3
Now we'll use our sphere formula:
for the lead,
(4/3)πr^3 = 6172.8395
r^3 = 1473.65...
r = (1473.65...)^(1/3) = appr 11.38 cm
for the aluminum,
(4/3)πr^3 = 26022.305
r^3 = 6212.367...
r = 18.38 cm
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.