Asked by Joel

a fair spinner has 11 equal sections 4 red 4 blue 3 green
it is spun twice
what is the probability of getting not green then green
Answered by mathhelper
well, if 3 of the 11 are green, then 8 must be not-green.

Prob(not green, then green) = (8/11)(3/11) = 24/121
Answered by Joel
HHHHHEEEELLLPPPP
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