Asked by King
Math
A carpenter constructed a closed wooden box with internal measurements 1.5m long 0.8m width and 1m high. wood used in constructing the box was 1cm thick and density of 0.6g/cm. Find volume of the wood used in constructing the box
2.mass of the box in kg correct to 1decimal place
A carpenter constructed a closed wooden box with internal measurements 1.5m long 0.8m width and 1m high. wood used in constructing the box was 1cm thick and density of 0.6g/cm. Find volume of the wood used in constructing the box
2.mass of the box in kg correct to 1decimal place
Answers
Answered by
King
I want an answer
Answered by
Bosnian
L = Length
L = 1.5 m = 150 cm
W = Width
W = 0.8 m = 80 cm
H = Height
H = 1 m = 100 cm
Volume of the outside side of the box:
Vo = L ∙ W ∙ H = 150 ∙ 80 ∙ 100 = 1 200 000 cm³
The dimensions of the inner side are less than 1 cm thick on the right side and 1 cm thick on the left side.
So the internal dimensions are less than the external dimensions by 2 cm.
Volume of the internal side of the box:
Vi = ( L - 2 ) ∙ ( W - 2 ) ∙ ( H - 2 ) = 148 ∙ 78 ∙ 98 = 1 131 312 cm³
Volume of the wood = Volume of the outside side of the box - Volume of the internal side of the box
Ww= Vo - Vi = 1 200 000 - 1 131 312 = 68 688 cm³
1 kg = 1000 g
1 g = 1 kg / 1000
Density:
ρ = 0.6 g / cm³
ρ = ( 0.6 g / cm³ ) / 1000
ρ = 0.0006 kg / cm³
Mass of the box = Density ∙ Volume of the wood
m = 0.0006 kg / cm³ ∙ 68 688 cm³ = 28.0704 kg
m = 28.1 kg
to one decimal place
Remark:
28.0704 kg is 0.0704 kg away from 28 kg and 0.0296 kg from away 28.1 kg.
So 28.0704 kg is closer to 28.1 kg than 28 kg
L = 1.5 m = 150 cm
W = Width
W = 0.8 m = 80 cm
H = Height
H = 1 m = 100 cm
Volume of the outside side of the box:
Vo = L ∙ W ∙ H = 150 ∙ 80 ∙ 100 = 1 200 000 cm³
The dimensions of the inner side are less than 1 cm thick on the right side and 1 cm thick on the left side.
So the internal dimensions are less than the external dimensions by 2 cm.
Volume of the internal side of the box:
Vi = ( L - 2 ) ∙ ( W - 2 ) ∙ ( H - 2 ) = 148 ∙ 78 ∙ 98 = 1 131 312 cm³
Volume of the wood = Volume of the outside side of the box - Volume of the internal side of the box
Ww= Vo - Vi = 1 200 000 - 1 131 312 = 68 688 cm³
1 kg = 1000 g
1 g = 1 kg / 1000
Density:
ρ = 0.6 g / cm³
ρ = ( 0.6 g / cm³ ) / 1000
ρ = 0.0006 kg / cm³
Mass of the box = Density ∙ Volume of the wood
m = 0.0006 kg / cm³ ∙ 68 688 cm³ = 28.0704 kg
m = 28.1 kg
to one decimal place
Remark:
28.0704 kg is 0.0704 kg away from 28 kg and 0.0296 kg from away 28.1 kg.
So 28.0704 kg is closer to 28.1 kg than 28 kg
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