Asked by Anonymous
I have two mathematically similar shapes, one of which has a volume of 1 litre and one which has a volume of half a litre. If the largest shape has a height of 40 cm, what (in centimetres) is the height of the smaller shape?
Answers
Answered by
mathhelper
The volumes of similar shapes are proportional to the cubes of their corresponding sides, so
1 L / .5 L = 40^3 cm^3 / s^3 cm^3
cancelling the units
1 / .5 = 40^3/s^3
s^3 = .5(64,000) = 32,000
s = 32000^(1/3) = appr 31.748 cm
check"
40^3 : 31.748^3
= 64000 : 32000
= 2 : 1
1 L / .5 L = 40^3 cm^3 / s^3 cm^3
cancelling the units
1 / .5 = 40^3/s^3
s^3 = .5(64,000) = 32,000
s = 32000^(1/3) = appr 31.748 cm
check"
40^3 : 31.748^3
= 64000 : 32000
= 2 : 1
Answered by
oobleck
the ratio of volumes is the cube of the ratio of heights.
So the ratio of heights is 1:∛2
40/∛2 = 31.748
So the ratio of heights is 1:∛2
40/∛2 = 31.748
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