Asked by anna
                A bacteria has a growth rate constant of 0.02. If initially, the number of bacteria is 1000, what is the time before it reaches a population of 100,000?
            
            
        Answers
                    Answered by
            oobleck
            
    So, you have P(t) = 1000 e^(.02t)
so solve
1000 e^(.02t) = 100,000
e^(.02t) = 100
.02t = ln100
t = ln100/.02 = 230.26
    
so solve
1000 e^(.02t) = 100,000
e^(.02t) = 100
.02t = ln100
t = ln100/.02 = 230.26
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