Asked by help plz
Which one of the following angles is not a solution of 2cos^2q = 1+sinq ?
(A) 90° (B) 180° (C)270° (D) 450° (E) none of the above.
(A) 90° (B) 180° (C)270° (D) 450° (E) none of the above.
Answers
Answered by
mathhelper
2cos^2 x = 1+sinx
2(1 - sin^2 x) = 1 + sinx
2 - 2sin^2 x = 1 + sinx
2sin^2 x + x -1 = 0
(2sinx - 1)(sinx + 1) = 0
sinx = 1/2, so x = 30°, 150°
or
sinx = -1, so x = 270°
so which of those things is not like the other?
2(1 - sin^2 x) = 1 + sinx
2 - 2sin^2 x = 1 + sinx
2sin^2 x + x -1 = 0
(2sinx - 1)(sinx + 1) = 0
sinx = 1/2, so x = 30°, 150°
or
sinx = -1, so x = 270°
so which of those things is not like the other?
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