Asked by Banky
A fixed mass of a has occupies a volume of 819cubic unit at the 0°c.if the gas is cooled at constant pressure,calculate the temperature at which it volume drop to 180cubic unit,calculate the temperature
Answers
Answered by
Anonymous
P V = n R T
P constant
V from 819 to 180
n constant
R constant
T from 273 to T
so
T/V= P / nR = constant
or
T1/V1 = T2/V2
273 / 819 = T2 / 180
T2 = 60 degrees Kelvin = 60 - 273 = -213 deg C
P constant
V from 819 to 180
n constant
R constant
T from 273 to T
so
T/V= P / nR = constant
or
T1/V1 = T2/V2
273 / 819 = T2 / 180
T2 = 60 degrees Kelvin = 60 - 273 = -213 deg C
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