Asked by Anonymous
Two points on the polar plane are given as P(−2, 3π/2 ) and Q(2, 2π/3). Find the triangular area formed by P, Q, and the pole.
(A) 1/2 (B) 1 (C) √2 (D) √3
(A) 1/2 (B) 1 (C) √2 (D) √3
Answers
Answered by
mathhelper
(-2,3π/2) = (2, π/2)
angle between them is 2π/3 - π/2 = π/6 ....... (think of it as 120° - 90° = 30°)
area = (1/2)(2)(sin π/6 )
= (1/2)(4)(1/2) = 1 square unit
angle between them is 2π/3 - π/2 = π/6 ....... (think of it as 120° - 90° = 30°)
area = (1/2)(2)(sin π/6 )
= (1/2)(4)(1/2) = 1 square unit
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