Question

prove that

(tanx + tany) / (cotx + coty) = (tanx)(tany)
cotx + coty = 1/tanx + 1/tany = (tanx + tany)/(tanx tany)
now just do the division

Related Questions

Show that tanx= (sinx/ cosx) can be written as: tan(x-y) = (tanx - tany) / (1+ tanxtany) Prove cotx-1/cotx+1 = sec2x - tan2x I prove till cotx-1/cotx+1 =1/1+tanx - tanx/1+tanx For this question, they want me to use fundamental trig identities to simplify the expression. The p...