Asked by hani
a 1640kg lift truck with rubber tires is skidding across the concrete. there is no applied force on the truck. if the acceleration of the truck is 5m/s ^2 backwards, what is the force of friction on the truck
Answers
Answered by
Anonymous
F = m a
F = -1640 * 5 = - 8200 Newtons
F = -1640 * 5 = - 8200 Newtons
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