If I have interpreted the question correctly, we have 116 g NaBr + 100 g H2O for a total of 116 g + 100 g = 216 g total so
% NaBr = (116/216)*100 = ?
) A saturated aqueous solution of NaBr at 20 oC contains 116 g NaBr / 100 H2O g. Express
this composition as percent by mass
1 answer
1 answer