Asked by Jamie
If D varies jointly as the square of E and F, and D = 210 , when E = 32 and F = 70
Answers
Answered by
mathhelper
D = k(EF)^2
when D = 210, E = 32 , and F = 70
210 = k(32*70)^2
210 = k(5017600)
k = 3/71680
D = (3/71680)(EF)^2
so , now what?
when D = 210, E = 32 , and F = 70
210 = k(32*70)^2
210 = k(5017600)
k = 3/71680
D = (3/71680)(EF)^2
so , now what?
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