Asked by haeraaa
The arithmetic sequence 2, 6, 10, … 90. The number of terms in the sequence is .....
Answers
Answered by
mathhelper
a = 2, d = 4
term(n) = a + (n-1)d
2 + (n-1)(4) = 90
4(n-1) = 88 , divide each side by 4
n-1 = 22
n = 23
you have 23 terms
term(n) = a + (n-1)d
2 + (n-1)(4) = 90
4(n-1) = 88 , divide each side by 4
n-1 = 22
n = 23
you have 23 terms