Question

∫[2,6] (1/x^2)
by hand

Answer 1

just use the power rule, and note thet d/dx (-1/x) = 1/x^2
∫[2,6] (1/x^2) dx = -1/x [2,6] = (-1/6)-(-1/2) = ____

Answer 2

∫ 1 / x² dx = - 1 / x

6
∫ 1 / x² dx =
2

- 1 / 6 - ( - 1 / 2 ) = - 1 / 6 + 1 / 2 = - 1 / 6 + 3 / 6 = 2 / 6 = 2 ∙ 1 / 2 ∙ 3 = 1 / 3