Form a quadratic equation in x whose roots are -3 and 1/4.

2 answers

For quadratic equation:

a x² + b x + c = a ( x - x1 ) ( x - x2 )

where x1 and x2 are roots

In this case x1 = - 3 , y = 1 / 4

a x² + b x + c = a [ x - ( - 3 ) ] ( x - 1 / 4 ) =

a ( x + 3 ) ( x - 1 / 4 ) = a ( x² + 3 x - 1 / 4 x - 3 / 4 ) =

a ( x² + 12 / 4 x - 1 / 4 x - 3 / 4 ) = a ( x² + 11 / 4 x - 3 / 4 )

where a is some real number ( leading coefficient of quadratic equation )
since you don't specify any particular form, just use the roots directly
(x+3)(4x-1) = 0
You can massage that as you will.
Similar Questions
    1. answers icon 2 answers
  1. SOLVING QUADRATICEQUATIONS 14. Determine the number of real roots, the axis of symmetry, and the vertex of each equation. a. y =
    1. answers icon 1 answer
    1. answers icon 1 answer
  2. which type of quadratic equation is most useful?Finding x-intercepts (a.k.a zeros, solutions, roots) is it standard form, vertex
    1. answers icon 1 answer
more similar questions