Question
Form a quadratic equation in x whose roots are -3 and 1/4.
Answers
Bosnian
For quadratic equation:
a x² + b x + c = a ( x - x1 ) ( x - x2 )
where x1 and x2 are roots
In this case x1 = - 3 , y = 1 / 4
a x² + b x + c = a [ x - ( - 3 ) ] ( x - 1 / 4 ) =
a ( x + 3 ) ( x - 1 / 4 ) = a ( x² + 3 x - 1 / 4 x - 3 / 4 ) =
a ( x² + 12 / 4 x - 1 / 4 x - 3 / 4 ) = a ( x² + 11 / 4 x - 3 / 4 )
where a is some real number ( leading coefficient of quadratic equation )
a x² + b x + c = a ( x - x1 ) ( x - x2 )
where x1 and x2 are roots
In this case x1 = - 3 , y = 1 / 4
a x² + b x + c = a [ x - ( - 3 ) ] ( x - 1 / 4 ) =
a ( x + 3 ) ( x - 1 / 4 ) = a ( x² + 3 x - 1 / 4 x - 3 / 4 ) =
a ( x² + 12 / 4 x - 1 / 4 x - 3 / 4 ) = a ( x² + 11 / 4 x - 3 / 4 )
where a is some real number ( leading coefficient of quadratic equation )
oobleck
since you don't specify any particular form, just use the roots directly
(x+3)(4x-1) = 0
You can massage that as you will.
(x+3)(4x-1) = 0
You can massage that as you will.