Asked by me
form a quadratic equation whose roots are 2.5+root3 and 2.5-root3 giving your answer in the form ax^2+bx+c=0 where a, b and c are integers.
Answers
Answered by
oobleck
y = (x - (5/2 + √3))(x - (5/2 - √3))
y = ((x - 5/2)^2 - 3)
y = x^2 - 5x + 13/4
y = 4x^2 - 20x + 13
y = ((x - 5/2)^2 - 3)
y = x^2 - 5x + 13/4
y = 4x^2 - 20x + 13
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