Asked by Anonymous
Max has a jar of sweets.
All of the sweets are either hard or soft.
There are twice as many hard sweets as soft
sweets.
1/5 of the hard sweets are red.
3/10 of the soft sweets are red.
There are 91 red sweets in total.
Work out the number of sweets in the jar.
All of the sweets are either hard or soft.
There are twice as many hard sweets as soft
sweets.
1/5 of the hard sweets are red.
3/10 of the soft sweets are red.
There are 91 red sweets in total.
Work out the number of sweets in the jar.
Answers
Answered by
oobleck
h = 2s
1/5 h + 3/10 s = 91
2/5 s + 3/10 s = 91
7/10 s = 91
s = 91 * 10/7 = 130
h = 2s = 260
h+s = 390 sweets in all
1/5 h + 3/10 s = 91
2/5 s + 3/10 s = 91
7/10 s = 91
s = 91 * 10/7 = 130
h = 2s = 260
h+s = 390 sweets in all
Answered by
mathhelper
number of hards ---- h
number of softs ---- s
but h = 2s
reds = (1/5)h + (3/10)s = 91
times 10
2h + 3s = 910
sub in h = 2s
2(2s) + 3s = 910
7s = 910
s = 130 , then h = 260 , for a total of 390
number of softs ---- s
but h = 2s
reds = (1/5)h + (3/10)s = 91
times 10
2h + 3s = 910
sub in h = 2s
2(2s) + 3s = 910
7s = 910
s = 130 , then h = 260 , for a total of 390
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