Asked by susu
A company's revenue from selling x units of an item is given as
R
=1700x−x^2. If sales are increasing at the rate of 45 units per day, how rapidly is revenue increasing (in dollars per day) when 290 units have been sold?
R
=1700x−x^2. If sales are increasing at the rate of 45 units per day, how rapidly is revenue increasing (in dollars per day) when 290 units have been sold?
Answers
Answered by
mathhelper
R = 1700 - x^2
dR/dt = -2x dx/dt, but we are told that dx/dt = 45 units/day
= -2(290)(45) = ....
Your equation of R = 1700 - x^2 doesn't make sense.
Why would the Revenue decrease as the sales increase?
I assume that x represents sales.
You sure it wasn't R = 1700 + x^2 ?
look into it
dR/dt = -2x dx/dt, but we are told that dx/dt = 45 units/day
= -2(290)(45) = ....
Your equation of R = 1700 - x^2 doesn't make sense.
Why would the Revenue decrease as the sales increase?
I assume that x represents sales.
You sure it wasn't R = 1700 + x^2 ?
look into it
Answered by
susu
A company's revenue from selling x units of an item is given as R=1700x−x^2. If sales are increasing at the rate of 45 units per day, how rapidly is revenue increasing (in dollars per day) when 290 units have been sold?
I am sure that R=1700x−x^2
I am sure that R=1700x−x^2
Answered by
susu
Let A be the area of a circle with radius r. If dr/dt=2 , find dA/dt when r=2.
Answered by
susu
For the parametric curve x=t2;y=t3 ,
evaluate the curvature (2nd derivative) when t=3
evaluate the curvature (2nd derivative) when t=3
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