Asked by Allie
Two streets meet at an 60° angle. At the corner, a park is being built in the shape of a triangle. Find the area of the park if, along one road, the park measures 180 feet, and along the other road, the park measures 200 feet.
(To the extent possible use standard angles to simplify your responses. When necessary express your answers using the functions sin, cos, sin−1, cos−1. If there is no solution enter IMPOSSIBLE.)
(To the extent possible use standard angles to simplify your responses. When necessary express your answers using the functions sin, cos, sin−1, cos−1. If there is no solution enter IMPOSSIBLE.)
Answers
Answered by
mathhelper
If we are given 2 sides and the contained angle of a triangle, we have
a nice little formula to find the area.
Area = (1/2)a*b*sinθ, were a and be are the two sides and θ is the
contained angle.
You have exactly that condition
area =(1/2)(180)(200)sin60°
= 18000(√3/2)
= 9000√3 square ft
a nice little formula to find the area.
Area = (1/2)a*b*sinθ, were a and be are the two sides and θ is the
contained angle.
You have exactly that condition
area =(1/2)(180)(200)sin60°
= 18000(√3/2)
= 9000√3 square ft
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