Asked by Rational Boi
Find an equation of a rational function with the following characteristics:
x-int of 5, y-int of -5/8, vertical asymptote x=-8/5, horizontal asymptote y=1/3
What is a possible answer and how did you arrive at each step?
x-int of 5, y-int of -5/8, vertical asymptote x=-8/5, horizontal asymptote y=1/3
What is a possible answer and how did you arrive at each step?
Answers
Answered by
oobleck
vertical asymptote
y = a/(5x+8)
x-int
y = a(x-5)/(5x+8)
horizontal asymptote
y = (5/3)(x-5)/((5x+8)) = (5x-25)/(15x+24)
This has a y-intercept of -25/24
So, how will you adjust it to get -5/8?
you want y(0) = -5/8, so
y = a/(5x+8)
x-int
y = a(x-5)/(5x+8)
horizontal asymptote
y = (5/3)(x-5)/((5x+8)) = (5x-25)/(15x+24)
This has a y-intercept of -25/24
So, how will you adjust it to get -5/8?
you want y(0) = -5/8, so
Answered by
Rational Boi
How would I continue from there?
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