Asked by math dumb
Find an equation of a rational function that satisfies the following conditions:
• Vertical asymptotes: x = −3
• Horizontal asymptote: y=3/2
• x -intercept: 5
• Hole at x =2
• Vertical asymptotes: x = −3
• Horizontal asymptote: y=3/2
• x -intercept: 5
• Hole at x =2
Answers
Answered by
oobleck
• Vertical asymptotes: x = −3
y = 1/(x+3)
• Hole at x =2
y = (x-2)/((x+3)(x-2))
• x -intercept: 5
y = ((x-2)(x-5))/((x+3)(x-2))
• Horizontal asymptote: y=3/2
y = (3(x-2)(x-5))/(2(x+3)(x-2))
graph with your favorite utility to confirm.
y = 1/(x+3)
• Hole at x =2
y = (x-2)/((x+3)(x-2))
• x -intercept: 5
y = ((x-2)(x-5))/((x+3)(x-2))
• Horizontal asymptote: y=3/2
y = (3(x-2)(x-5))/(2(x+3)(x-2))
graph with your favorite utility to confirm.
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