Asked by Anthony
                 solve. 2x + 12 ≥ 6 
x ≥ -3
x ≤ 3
x ≤ -3
x ≥ 3
            
        x ≥ -3
x ≤ 3
x ≤ -3
x ≥ 3
Answers
                    Answered by
            Bosnian
            
    2x + 12 ≥ 6 
Subtract 12 to both sides
2x ≥ - 6
Divider both sides by 2
x ≥ - 3
    
Subtract 12 to both sides
2x ≥ - 6
Divider both sides by 2
x ≥ - 3
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