Asked by Max
Please help me with these chemistry questions🙏
1. Calculate the pOH of 0.093 M LiOH.
2. Calculate the hydroxide ion concentration, [OH-], in 1.36 M HNO3.
1. Calculate the pOH of 0.093 M LiOH.
2. Calculate the hydroxide ion concentration, [OH-], in 1.36 M HNO3.
Answers
Answered by
DrBob222
1. Calculate the pOH of 0.093 M LiOH.
Since LiOH is a strong base it will ionize completely and (OH^-) = 0.093. Then pOH = -log (OH^-). Substitute and solve for pOH.
2. Calculate the hydroxide ion concentration, [OH-], in 1.36 M HNO3.
HNO3 is a strong acid. It ionizes complely so (H^+) = 1.36 M.
pH = -log(H^+) = -log(1.36). Then
pH + pOH = pKw = 14. You know pKw and pH, solve for pOH.
Post your work if you get stuck.
Since LiOH is a strong base it will ionize completely and (OH^-) = 0.093. Then pOH = -log (OH^-). Substitute and solve for pOH.
2. Calculate the hydroxide ion concentration, [OH-], in 1.36 M HNO3.
HNO3 is a strong acid. It ionizes complely so (H^+) = 1.36 M.
pH = -log(H^+) = -log(1.36). Then
pH + pOH = pKw = 14. You know pKw and pH, solve for pOH.
Post your work if you get stuck.
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