Asked by TM

Joseph traveled from Boston to Framingham at 50 mph and then back to Boston at 40 mph. What was Joseph's average speed on the round trip?
Answered by mathhelper
Key fact:
the distance is the same each way

time to go from B to F = d/50
time to go from F to B = d/40

avg speed = total distance/total time
= 2d/(d/50 + d/40)
= 2d/[(4d + 5d)/200]
= 2d * (200)/9d
= 400/9 or appr 44.4 mph
Answered by balls
Joseph traveled from Boston to Framingham at 50 mph and then back to Boston at 40 mph. What was Joseph's average speed on the round trip?
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