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Original Question
A scientist measures the standard enthalpy change for the following reaction to be -53.4 kJ : Ca(OH)2(aq) + 2 HCl(aq) CaCl2(s)...Asked by Anonymous
A scientist measures the standard enthalpy change for the following reaction to be -20.2 kJ :
Ca(OH)2(aq) + 2 HCl(aq)CaCl2(s) + 2 H2O(l)
Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of HCl(aq) is kJ/mol.
Answers
Answered by
DrBob222
Do this to get started.
Look up the standard enthalpy of the other material.
Substitute into the following equation.
dHrxn = (n*dHo products) - (n*dHo reactants)
dH rxn is given in the problem. Substitute the number you look up and solve for the single unknown.
Post your work if you get stuck.
Look up the standard enthalpy of the other material.
Substitute into the following equation.
dHrxn = (n*dHo products) - (n*dHo reactants)
dH rxn is given in the problem. Substitute the number you look up and solve for the single unknown.
Post your work if you get stuck.
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