Asked by Austin
A scientist measures the standard enthalpy change for the following reaction to be -53.4 kJ :
Ca(OH)2(aq) + 2 HCl(aq) CaCl2(s) + 2 H2O(l)
Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of H2O(l) is kJ/mol
Ca(OH)2(aq) + 2 HCl(aq) CaCl2(s) + 2 H2O(l)
Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of H2O(l) is kJ/mol
Answers
Answered by
DrBob222
Do you have the dHf values for the other materials in the reaction? I don't have them in my text.
dHrxn = (n*dHf products) - (n*dH reactants). Substitute and solve for dH H2O.
dHrxn = (n*dHf products) - (n*dH reactants). Substitute and solve for dH H2O.