Asked by jonathan
Given ln(m)=4,ln(n)=−7 and ln(p)=−8, evaluate:
ln(e^7n^4/sqrt(mp))
can you explain how to get the answer ..thanks
ln(e^7n^4/sqrt(mp))
can you explain how to get the answer ..thanks
Answers
Answered by
mathhelper
Use your log rules ...
ln(e^7n^4/sqrt(mp))
= ln (e^7) + ln (n^4) - ln (mp)^(1/2)
= 7lne + 4ln n - (1/2) (ln m + ln p)
now just sub in the given values, remember that ln e = 1
ln(e^7n^4/sqrt(mp))
= ln (e^7) + ln (n^4) - ln (mp)^(1/2)
= 7lne + 4ln n - (1/2) (ln m + ln p)
now just sub in the given values, remember that ln e = 1
Answered by
jonathan
is it -19?
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