Asked by Cherish
The third and seventh terms of an ap are respectively -2 and 10 find the value of the first term and number of term which must be add to give sum of 410
Answers
Answered by
Cherish
Where is the answer
Answered by
Cherish
Where is the working
Answered by
Goodness
Am asking the same question
Answered by
Anonymous
Tn = a + (n-1) d
so for example T3 = a + 2 d and T7 = a + 6 d
that gives you two linear equations to solve for a and d
then use the equation for sum of terms to find the n for sum of 410
so for example T3 = a + 2 d and T7 = a + 6 d
that gives you two linear equations to solve for a and d
then use the equation for sum of terms to find the n for sum of 410
Answered by
Anonymous
If you do not understand what I said, Google:
Math is Fun arithmetic sequence
Math is Fun arithmetic sequence
Answered by
Anonymous
I am not about to do it for you. It is pure plug and chug.
Answered by
oobleck
a+2d = -2
a+6d = 10
solve for a and d, and then you have
n/2 (2a+(n-1)d) = 410
Since you now know a and d, just use them to solve for n
a+6d = 10
solve for a and d, and then you have
n/2 (2a+(n-1)d) = 410
Since you now know a and d, just use them to solve for n
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