Question
The sum of third and seventh term of an ascending arithmetic progression is 12 and their product is 32.
Then find the ninth term?
Then find the ninth term?
Answers
Steve
c'mon, guy - use what you know abot APs:
(a+2d)+(a+6d) = 12
(a+2d)(a+6d) = 32
Now just solve for a and d, then you want a+8d.
Hint: 4*8 = 32
(a+2d)+(a+6d) = 12
(a+2d)(a+6d) = 32
Now just solve for a and d, then you want a+8d.
Hint: 4*8 = 32