Asked by Jay Mehta

The sum of third and seventh term of an ascending arithmetic progression is 12 and their product is 32.
Then find the ninth term?

Answers

Answered by Steve
c'mon, guy - use what you know abot APs:

(a+2d)+(a+6d) = 12
(a+2d)(a+6d) = 32

Now just solve for a and d, then you want a+8d.

Hint: 4*8 = 32
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