Asked by Abigail
Giving the density of water at 16^°c is 1.0037mg/ml.Show how you will prepare 250mls of 0.4M H2SO4 solution at this temperature from a stock solution with a specific gravity of 1.84 and concentration of 98%w/w.
Answers
Answered by
DrBob222
Note: You made a typo. You must have meant that the density of H2O @ 16 C is 1.0037 g/mL and not 1.0037 mg/mL.
Specific Gravity of stock H2SO4 solution is 1.84.
Therefore, density of stock H2SO4 = S.G x density H2O @ 16 C.
So density of stock H2SO4 = 1.84 x 1.0037 g/mL = 1.8468 which I will round to 1.85 g/mL.
Then M = 1.85 g/mL x 1000 mL x 0.98 x (1 mol H2SO4/98 g H2SO4) = 18.5 M. Now use the dilution formula of
mL1 x M1 = mL2 x M2
250 mL x 0.4 M H2SO4 = mL2 x 18.5 M H2SO4
Solve for mL2. Take that many mL of the stock, transfer to a 250 mL volumetric flask, add DI or distilled water to the flask to the mark, stopper, mix thoroughly, label. Done.
Specific Gravity of stock H2SO4 solution is 1.84.
Therefore, density of stock H2SO4 = S.G x density H2O @ 16 C.
So density of stock H2SO4 = 1.84 x 1.0037 g/mL = 1.8468 which I will round to 1.85 g/mL.
Then M = 1.85 g/mL x 1000 mL x 0.98 x (1 mol H2SO4/98 g H2SO4) = 18.5 M. Now use the dilution formula of
mL1 x M1 = mL2 x M2
250 mL x 0.4 M H2SO4 = mL2 x 18.5 M H2SO4
Solve for mL2. Take that many mL of the stock, transfer to a 250 mL volumetric flask, add DI or distilled water to the flask to the mark, stopper, mix thoroughly, label. Done.
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