Asked by Anant shukla
The density of water of ice is 0.917gm/cm-3 and the density of sea water is 1.03gm/cm-3.calculate the ratio volume of ice outside to the volume of ice which is inside the sea water
Answers
Answered by
Damon
say we have a cubic piece of ice one centimeter on a side floating on water:
Ice volume = 1.000 cm^3
Ice mass = .917 g
so
mass of water displaced = .917 g
volume of water displaced = .917 g/1.03 g/cm^3
= .890 cm^3 which is the volume of ice below water surface
volume of ice above water = 1.000-.890 = .110 cm^3
so volume above water / volume below water
= 0.110/.890 = 0.123
Ice volume = 1.000 cm^3
Ice mass = .917 g
so
mass of water displaced = .917 g
volume of water displaced = .917 g/1.03 g/cm^3
= .890 cm^3 which is the volume of ice below water surface
volume of ice above water = 1.000-.890 = .110 cm^3
so volume above water / volume below water
= 0.110/.890 = 0.123
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.