Asked by Fa11enAnge106

Which element would most likely lose electrons to form positive ions when bonding with other elements?

A: Gallium (Ga)

B: Rubidium (Rb)

C: Iodine (I)

D: Argon (Ar)

Answers

Answered by Anonymous
Ga has 31 protons and is a metal in group IIIA of table, forms +3 ion by losing 3 electrons
Answered by DrBob222
Gallium is a correct answer and for the reason cited.
However, I think Rb is a better answer since the question asks for the "most likely". Rb is far more reactive than Ga. If for no othr reason, Rb has only one electron to lose while Ga has three to lose and the ionization potential for Rb (with one electron) is lower than that of Ga (with three electrons)..
Answered by Fa11enAnge106
thank you both
Answered by No one
rubidium (Rb)
The sodium atom transfers electrons to the chlorine atoms to form ionic bonds.
nitrogen (N) and oxygen (O)
the relative strength with which an element attracts electrons in a chemical bond
bromine and nitrogen

100% correct
Answered by ves
no one is 100% correct!!!
Answered by BOBBY JR
@no one. I could kiss you RN ;)
Answered by BOBBY JR
BTW @no one is 100000000000% correct
Answered by I hate furries
1) rubidium (Rb)

2) The sodium atom transfers electrons to the chlorine atoms to form ionic bonds.

3) nitrogen (N) and oxygen (O)

4) the relative strength with which an element attracts electrons in a chemical bond

5) bromine and nitrogen
Answered by i hate life lol
i hate furries is correct tysmmm
Answered by same ✌
Thank you!
Answered by plaguedocter
lol how ironic that a furry used a furry haters answers to check theirs and it was 100%
care not
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