Asked by umar faruq

Log5(3/5)+3log5(15/2)-log5(81/8)
Answered by mathhelper
Log5(3/5)+3log5(15/2)-log5(81/8)
= Log5(3/5)+log5((15/2)^3)-log5(81/8)
= log5[ (3/5)(3375/8) ÷ (81/8) ]
= log5 [25]
= 2
Answered by oobleck
assuming all logs have base 5, we have
log(3/5)+3log(15/2)-log(81/8)
= log3 - log5 + 3(log3+log5-log2) - 4log3 + 3log2
= log3 - log5 + 3log3 + 3log5 - 3log2 - 4log3 + 3log2
= 2log5
and since log5(5) = 1, the final value is 2, as above
Answered by Emmanuel ojiri
Wonderful answer
Answered by Emmanuel ojiri
Wonderful answer like this page
Answered by Oluwaferai
2
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