Asked by g.o.
Draw a diagram and find:
P is between E and F with PE=5x−4, EF=30, and PF=3x+2. FInd x, PE, and PF.
x =
PE =
PF =
P is between E and F with PE=5x−4, EF=30, and PF=3x+2. FInd x, PE, and PF.
x =
PE =
PF =
Answers
Answered by
R_scott
PE + PF = EF ... 5x - 4 + 3x + 2 = 30
8x - 2 = 30
solve for x , then substitute back to find PE and PF
8x - 2 = 30
solve for x , then substitute back to find PE and PF
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