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Asked by Max

At a certain temperature, the equilibrium constant is 174 for

H2(g) + I2(g) ↔ 2HI(g)

Calculate the equilbrium constant for

0.5H2(g) + 0.5I2(g) ↔ HI(g)
4 years ago

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Answered by DrBob222
For the same equation but with 1/2 the coefficients, the new eq is sqrt (174).
4 years ago
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At a certain temperature, the equilibrium constant is 174 for

H2(g) + I2(g) ↔ 2HI(g)

Calculate the equilbrium constant for

0.5H2(g) + 0.5I2(g) ↔ HI(g)

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