Asked by Anonymous
I'm supposed to make f(x)= 3x^2 - 18x +28 into vertex form
I got f(x) = 3(x - 3)^2 + 1
My question what would be the vertex?
Would it be (3,1) or (-3,1) I'm confused by the - in front of the 3
I got f(x) = 3(x - 3)^2 + 1
My question what would be the vertex?
Would it be (3,1) or (-3,1) I'm confused by the - in front of the 3
Answers
Answered by
mathhelper
In the form
y = a(x-h)^2 + k
the vertex is (h,k), the value of a does not in any way affect with the
vertex
in yours, had the equation been y = 5(x-3)^2 + 1
the vertex would still be (3,1), the 5 has nothing to do with the vertex.
y = a(x-h)^2 + k
the vertex is (h,k), the value of a does not in any way affect with the
vertex
in yours, had the equation been y = 5(x-3)^2 + 1
the vertex would still be (3,1), the 5 has nothing to do with the vertex.
Answered by
Anon
I was so more asking about the - inside the parenthesis. Like the (x-3) so would you not also have to take the - in front of the 3?
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