Asked by Dre
A bag contains
4
white marbles,
5
red marbles, and
9
blue marbles.
If a marble is drawn from the bag, replaced, and another marble is drawn, what is the probability of drawing first a white marble, and then a blue marble?
A bag contains
5
green marbles,
9
blue marbles, and
4
red marbles.
If two different marbles are drawn from the bag, what is the probability of drawing first a green marble and then a red marble?
4
white marbles,
5
red marbles, and
9
blue marbles.
If a marble is drawn from the bag, replaced, and another marble is drawn, what is the probability of drawing first a white marble, and then a blue marble?
A bag contains
5
green marbles,
9
blue marbles, and
4
red marbles.
If two different marbles are drawn from the bag, what is the probability of drawing first a green marble and then a red marble?
Answers
Answered by
mathhelper
1.
prob(white, then blue) = (4/18)(9/18) = 1/9 , with the first marble returned.
2. assuming the first marble is not returned
prob(green, then red) = (5/18)(4/17) = 10/153
prob(white, then blue) = (4/18)(9/18) = 1/9 , with the first marble returned.
2. assuming the first marble is not returned
prob(green, then red) = (5/18)(4/17) = 10/153
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