A-Rod, two posts below, had a similar question, take a look at my
reply to that one, and see if applies to yours as well.
Suppose f(x)= 1/x and g(x)= x-2. Also, suppose h(x)=f(g(x)). Then h(x)= 1 / (x-2). Find the domain of h(x)= 1 / (x-2). Express the domain using inequality notation.
6 answers
I'm still a bit confused sorry.
The h(x)= is throwing me off. Then I also don't know how to express the domain using inequality notation.
The h(x)= is throwing me off. Then I also don't know how to express the domain using inequality notation.
x ≠ 2
x<2 OR x>2
x ε (-∞,2)U(2,∞)
x<2 OR x>2
x ε (-∞,2)U(2,∞)
even though f(x)= 1/x is imbedded in h(x)
we have to restrict f(x) and say x ≠ 0.
from h(x)=f(g(x)) = 1/(x-2), we must have x ≠ 2
Since I am old school when it comes to the new notation, somebody
might want to kick in here.
I would say:
x ∈ R, x ≠ 0,2
we have to restrict f(x) and say x ≠ 0.
from h(x)=f(g(x)) = 1/(x-2), we must have x ≠ 2
Since I am old school when it comes to the new notation, somebody
might want to kick in here.
I would say:
x ∈ R, x ≠ 0,2
So would it be:
(-∞,2)U(2,∞)
OR
(-∞,0)U(0,2)U(2,∞)
(-∞,2)U(2,∞)
OR
(-∞,0)U(0,2)U(2,∞)
my ad
(-∞,0)U(0,2)U(2,∞)
(-∞,0)U(0,2)U(2,∞)