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How would you prepare 2.5 L of a 0.05 M solution of iron (III) chloride using iron (III) chloride hexahydrate?
Would you use the eqn,
Cinit x Vinit = Cfinal x Vfinal
So I have Cfinal and Vfinal... now what?
from 2.5 L of 0.05 M, how many of moles iron (III) chloride hexahydrate do you need?
Moles = volume x conc
then using number of moles
mass required = number of moles x (RMM of iron (III) chloride hexahydrate)
Then you dissolve this mass in water and make the volume up to 2.5 L.
What does the RMM mean?
Relative Molecular Mass
Explain Bot
answered
1 year ago
1 year ago