Question

You need to prepare a 0.0358 M solution of chloride ions with a volume of 625 mL. What mass (in g) of iron (III) chloride will you need to prepare this solution?

Answer 1

You need mols of M x L = 0.0358 x 0.625 L = ?
Then grams = mol x molar mass.
Post your work if you get stuck.