Asked by Sanji Vinsmoke

The velocity of an object is given for v=3.6t + 2(m/s) .Determine the displacement (in meters) for the time interval t1=1.7s and t2= 5.6s. The initial position x0=0

Answers

Answered by oobleck
x = 1.8t^2 + 2t
displacement is just x(5.6) - x(1.7)
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