Asked by Craig
For an object whose velocity in ft/sec is given by v(t) = -3t2 + 5, what is its displacement, in feet, on the interval t = 0 to t = 2 secs?
6.607
2
-2.303
2.303
6.607
2
-2.303
2.303
Answers
Answered by
Steve
s(T) = ∫[0,T] v(t) dt
you want
s(2) = ∫[0,2] -3t^2+5
= (-t^3+5t) [0,2] = 2
you want
s(2) = ∫[0,2] -3t^2+5
= (-t^3+5t) [0,2] = 2
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