A person walks first at a constant speed of 5.10 m/s along a straight line from point circled A to point circled B and then back along the line from circled B to circled A at a constant speed of 3.25 m/s.

Question

A person walks first at a constant speed of 5.10 m/s along a straight line from point circled A to point circled B and then back along the line from circled B to circled A at a constant speed of 3.25 m/s.
(a) What is her average speed over the entire trip?
d/delta t

oobleck · Answer

total distance = 2d total time = d/5.10 + d/3.25 average speed = 2/(1/5.10 + 1/3.25) = 3.97 m/s