Asked by babidi

A person walks first at a constant speed of 4.50 m/s along a straight line from point A to point B and then back along the line from B to A at a constant speed of 3.00 m/s.
(a) What is her average speed over the entire (b) What is her average velocity over the entire trip?
trip?
Answered by bobpursley
Let A to B be 100 miles, and B to A be 100 miles.
Distance=200 miles
So what is the time
timeAB=100/4.5 timeBA=100/3
add the times to get total time
average velocity=distance/totaltime
Velocity=displacement/time
= (finalposition-initialposition)/time
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