Asked by ryan
Mindy and Troy combined ate 9 pieces of the wedding cake. Mindy ate 3 pieces of cake and Troy had .25 of the total cake.
Answers
Answered by
Marcus Gonzalez
Mindy and troy combined 9 pieces of the wedding cake.
Mindy ate = 3 pieces of cake
Troy = had ¼ of the total cake.
Now, let’s find an equation that will give us the total number of pieces of the cake
=> Let X = Mindy
=> let Y = Troy
=> Let c = total number of cake
=> X + Y = 9, where x = 9 and y = ¼
Let’s find the number of pieces of cake that Troy’s have:
=> Y = 9 – x
=> Y = 9 – 3 = 6
=> Y = 6
Now, let’s find the number of Cake
=> 6 = c/4
=> c = 4 x 6
=> c = 24
Thus, there are 24 cakes in all.
Mindy ate = 3 pieces of cake
Troy = had ¼ of the total cake.
Now, let’s find an equation that will give us the total number of pieces of the cake
=> Let X = Mindy
=> let Y = Troy
=> Let c = total number of cake
=> X + Y = 9, where x = 9 and y = ¼
Let’s find the number of pieces of cake that Troy’s have:
=> Y = 9 – x
=> Y = 9 – 3 = 6
=> Y = 6
Now, let’s find the number of Cake
=> 6 = c/4
=> c = 4 x 6
=> c = 24
Thus, there are 24 cakes in all.
Answered by
mathhelper
That's much Ado About Nothing.
Mindy --- 3
Troy (1/4)c, where c is the total number of pieces
(1/4)c + 3 = 9
(1/4)c = 6
c = 24
Mindy --- 3
Troy (1/4)c, where c is the total number of pieces
(1/4)c + 3 = 9
(1/4)c = 6
c = 24
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.