Asked by samwithsmaleyes
An arch has the shape of a semi ellipse that is 10 ft. long and 3 ft. high at the center. How high is the arch at a point 2 ft. from the center? *
Answers
Answered by
mathhelper
We are told that 2a = 10 and 2b = 3
so the equation of the ellipse is
x^2/25 + y^2/2.25 = 1 , using x^2/a^2 + y^2/b^2 = 1
so when x = 2
4/25 + y^2/2.25 = 1
y^2/2.25 = 21/25
y^2 = 2.23(21/25) = 1.89
y = √1.89 = 1.375 ft
so the equation of the ellipse is
x^2/25 + y^2/2.25 = 1 , using x^2/a^2 + y^2/b^2 = 1
so when x = 2
4/25 + y^2/2.25 = 1
y^2/2.25 = 21/25
y^2 = 2.23(21/25) = 1.89
y = √1.89 = 1.375 ft
Answered by
oobleck
we have a = 5, b = 3
x^2/25 + y^2/9 = 1
now find y when x = 2
x^2/25 + y^2/9 = 1
now find y when x = 2
Answered by
mathhelper
Agree with oobleck.
I read the height to be the whole ellipse not the semi.
I read the height to be the whole ellipse not the semi.
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