Question

An electron is accelerated by a 5.2kv potential difference. How strong a magnetic field must be experienced by the electron if it’s path is a circle of radius 4.0cm

Answer 1

where
m = 9.11 * 10^-31 kg
q = 1.60* 10^-19 Coulombs

(1/2) m v^2 = q * 5.2 * 10^3
solve for v

R = 0.04 meters
for circle force= mass * centripetal acceleration
|q| v B = m v^2 / R
so
B = m v / (q R)

Answer 2

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