45 cm = 0.45 m
in air for time T
thrown at angle A from horizontal
u = constant horizontal speed = Vi cos A where Vi is initial speed of 15m/s
so
0.45 = u T= Vi cos A * T= 15 T cos A
so T cos A = 0.03
v = 15 sin A - g t
now fix the typos
A stone thrown from the top of vertical wall with a velocity of 15m/s hits the ground at a point 45cm from the base of the wall. Calculate the following:
I) time the stone spends in the air
II) the height of the wall
III) Draw a diagram of the given information
1 answer
1 answer