Asked by anon
What is the value of a charge if moving it 0.692m opposite to the direction of a 3470N/C electric field to store 5.53J?
a) 434C
b) -434C
c) 0.00230C
d) -0.00230C
a) 434C
b) -434C
c) 0.00230C
d) -0.00230C
Answers
Answered by
Anonymous
F = q E
work = F * distance = q E * 0.692
5.53 = q * 3470 * 0.692
q = 0.00230 plus because pushing uphill
work = F * distance = q E * 0.692
5.53 = q * 3470 * 0.692
q = 0.00230 plus because pushing uphill
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